X^2+28x=-29

Solution for X^2+28x=-29 equation:

X^2+28X=-29

We move all terms to the left:

X^2+28X-(-29)=0

We add all the numbers together, and all the variables

X^2+28X+29=0

a = 1; b = 28; c = +29;
Δ = b2-4ac
Δ = 282-4·1·29
Δ = 668
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{668}=\sqrt{4*167}=\sqrt{4}*\sqrt{167}=2\sqrt{167}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-2\sqrt{167}}{2*1}=\frac{-28-2\sqrt{167}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+2\sqrt{167}}{2*1}=\frac{-28+2\sqrt{167}}{2}
$